CHEM 2141 2006 Comments
This area is an updated comments section concerning CHEM 2141 Physical chemistry.
| 5/8/06 4th Clarification on Take Home Final
Problem 3e
-
This is a very tedious problem. But it ultimately involves two variables and two equations. Conceptually this problem should seem similar to those presented in homework #4. |
| 3rd Clarification on Take Home Final Exam
CHEM2141
Students:
If you are encountering difficulities with the exam problems please email me and I will respond to the group as in this email. I suggest doing the "easier" problems first (i.e. problems 1 & 4). Please have your lecture notes handy. I have received several inquires concerning problem 2d, 2e and 3a. So I have provided useful info below:
Problem
2d -
d.
(7 pts) For
This
problem is essentially a Harmonic oscillator of fundamental frequency n30
= 3026.758 cm-1. The value of the u qauntum
number (that we call u30
in this case) will be very high. Don't worry about the zero point
energy, because we are concerned with the energy in the highu state
minus the energy at u
= 0 (zero point energy). Thus the zero point energy is an offset.
For
more clarification see the solution to Homework 3 problem
8. Note the (0,3,0) is a state with 3 vibrational quanta for the n2
mode. So in this u
= 3, and the energy in wavenumbers = 3 x n2.
Note: This problem
is not computationally difficult, but it does involve conceptual
understanding of what we mean by a vibrational overtone, and the energy
(above the zero point energy) associated with the vibrational overtone.
Problem
2e -
e.
(5 pts) If the C-H bond energy in benzene is 515.5 kJ mol-1,
determine the maximum energy translational energy
in kJ mol-1 of a H atom ejected from the phenyl
radical following the 193 nm absorption of C6H6 to
form the phenyl radical and H atom. (Hint: similar to photoelectric
effect, except an atom is ejected instead of an electron).
In
the photoelectric effect you have to account for the conservation of
energy with the work function, photon energy & kinetic (translational) energy
of the electron. Similarly in this problem you also have 3 energies to
account for, which obey an energy conservation. Just be sure that you
are dealing with energies per mole, and not energies per molecule. Note
at the top of the exam: 83.6
cm-1
= 1 kJ mol-1
Problem 3a
-
(10
pts) Employ the steady-state approximation for [ClO4] to show
that
In lecture we were primarily concerned with simplifying the expression: d[product]/dt, but this problem asks for d[Cl2O6]/dt which has two terms: a production term and a depletion term. To add the two terms, you must make the denominators the same. For exam if you are adding 2/3 to 7. You multiply the numerator and denominator of 7/1 by 3 to get 21/3: 2/3 + 21/3 = 23/3. Utilize a similar approach for problem 3a of the Take Home Final exam. This problem (3a) along with 3e can be quite tedious, so work slowly and carefully.
|
| 5/3/06 Clarification on Take Home Final Exam
1b ii. On this problem I would like you to correlate the computed
value for
Please email me if you have any questions and I will post answers here
as well as email. |
| 4/18/06 Changes in Schedule Due to the power outage a
number of changes have been made:
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| 1/19/06 NO LATE HOMEWORK ACCEPTED! Homework #1 is due Friday Jan.20 5:00 PM. Please submit your homework to me by that time. I will not accept late homework! Note, I will be out of town tomorrow (Friday) morning, but will return to Charlotte Friday evening. If you are unable to submit your homework directly to me during class or in my office, please slide it under my office door (258 Burson). I plan to post the answers either Friday evening. Once the answers are posted I will not accept late homework. Usually I post answers by 5:05 PM. |
| 1/10/06 Welcome to the comment section. I will post comments from time to time. |
| Advice for CHEM2141 Daily
study tips Tips for the Exam |